Time | Variable |
---|---|
1 | 2.1 |
2 | 4.5 |
3 | 5.3 |
4 | 3.2 |
5 | 1.6 |
Time | Variable | Lag |
---|---|---|
1 | 2.1 | |
2 | 4.5 | 2.1 |
3 | 5.3 | 4.5 |
4 | 3.2 | 5.3 |
5 | 1.6 | 3.2 |
Time | Variable | Lag |
---|---|---|
1 | 2.1 | |
2 | 4.5 | 2.1 |
3 | 5.3 | 4.5 |
4 | 3.2 | 5.3 |
5 | 1.6 | 3.2 |
Correlation of a variable with its lag is first-order autocorrelation.
Time | Variable | 2nd Lag |
---|---|---|
1 | 2.1 | |
2 | 4.5 | |
3 | 5.3 | 2.1 |
4 | 3.2 | 4.5 |
5 | 1.6 | 5.3 |
Correlation of a variable with its 2nd lag is second-order autocorrelation.
Rearrange \[x_t = \alpha + \beta x_{t-1} + \varepsilon_t\] as \[\Delta x_t = \alpha + (\beta-1) x_{t-1} + \varepsilon_t\] \[\Delta x_t = (\beta-1)\left(x_{t-1} - \frac{\alpha}{1-\beta}\right) + \varepsilon_t\]
An AR(1) is \[\Delta x_t = (\beta-1)\left(x_{t-1} - \frac{\alpha}{1-\beta}\right) + \varepsilon_t\]
\(\beta<1\) implies regression towards the mean.
The mean is \(\alpha/(1-\beta)\).
\(|\beta-1|\) is called the rate of mean reversion.
\(\beta>1\) implies nonstationary.
Ask Julius to simulate the process x_t = 1 + 0.5*x_{t-1} + e_t by drawing 1,000 standard normals for e_t starting at x_0=1. Ask Julius to plot the process.